已知数列\(\{a _{n} \}\)，\(\{b _{n} \}\)满足\(a _{1} =b _{1} =1\)，对任意\(n∈N*\)均有\(a_{n+1}=a_{n}+b_{n}+ \sqrt { a_{ n }^{ 2 }+ b_{ n }^{ 2 }}\)，\(b_{n+1}=a_{n}+b_{n}- \sqrt { a_{ n }^{ 2 }+ b_{ n }^{ 2 }}\)，
\((1)\)证明：数列\(\{a _{n} +b _{n} \}\)和数列\(\{a _{n} \boldsymbol{⋅}b _{n} \}\)均为等比数列；
\((2)\)设\(c_{n}=(n+1)\cdot 2^{n}\cdot ( \dfrac {1}{a_{n}}+ \dfrac {1}{b_{n}})\)，求数列\(\{c _{n} \}\)的前\(n\)项和\(T _{n}\)．