已知100件产品中有3件次品\( ,\)现从中任意抽出5件\( ,\)则至少有2件次品的抽法种数是 ( )
A. \( {C}_{100}^{3}-{C}_{97}^{3}\)种
B. \( {C}_{3}^{2}{C}_{97}^{3}+{C}_{3}^{3}{C}_{97}^{2}\)种 C. \( {C}_{100}^{5}-{C}_{97}^{3}\)种 D. \( {C}_{3}^{1}{C}_{97}^{4}+{C}_{3}^{2}{C}_{97}^{3}+{C}_{3}^{3}{C}_{97}^{2}\)种
