已知数列\(\{a_{n}\}\)为等比数列，其前\(n\)项和为\(S_{n}\)，且\(S_{n}=λ\cdot 4^{n}-3λ+1(λ∈R)\)．
\((1)\)求\(\{a_{n}\}\)的通项公式；
\((2)\)设\(b_{n}=\log _{2}(S_{n}+ \dfrac {1}{2})+1\)，求数列\(\{ \dfrac {3b_{n}}{4a_{n}}\}\)的前\(n\)项和\(T_{n}\)．