设数列\(\{ a_{n}\}(n{=}1{,}2{,}3{…})\)的前\(n\)项和\(S_{n}\)，满足\(S_{n}{=}2a_{n}{-}a_{1}\)，且\(a_{1}{,}a_{2}{+}1{,}a_{3}\)成等差数列．
\((1)\)求数列\(\{ a_{n}\}\)的通项公式；
\((2)\)设数列\(\{\dfrac{1}{a_{n}}\}\)的前\(n\)项和为\(T_{n}\)，求\(T_{n}\)．