已知数列\(\{a_{n}\}\)满足：\(a_{1}+3a_{2}+3^{2}a_{3}+⋯+3^{n-1}a_{n}=\dfrac{n}{3}(n\in N^{*}).\)
\((1)\)求数列\(\{a_{n}\}\)的通项公式；
\((2)b_{n}=\dfrac{1}{3^{n+1}(1-a_{n})(1-a_{n+1})}\)，求数列\(\{b_{n}\}\)的前\(n\)项和\(S_{n}.\)