等差数列\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}\)，数列\(\{b_{n}\}\)是等比数列，满足\(a_{1}=3\)，\(b_{1}=1\)，\(b_{2}+S_{2}=10\)，\(a_{5}-2b_{2}=a_{3}\)．
\((\)Ⅰ\()\)求数列\(\{a_{n}\}\)和\(\{b_{n}\}\)的通项公式；
\((\)Ⅱ\()\)令\(Cn= \begin{cases} \dfrac {2}{S_{n}},n{为奇数} \\ b_{n,}n{为偶数}\end{cases}\)设数列\(\{c_{n}\}\)的前\(n\)项和\(T_{n}\)，求\(T_{2n}\)．