已知\(\{a _{n} \}\)是等差数列，其前\(n\)项和为\(S _{n}\)，\(\{b _{n} \}\)是正项递增的等比数列，且\(a _{1} =b _{1} =2\)，\(a _{3} =b _{3}\)，\(S _{5} -b _{5} =8\)．
\((1)\)求数列\(\{a _{n} \}\)与\(\{b _{n} \}\)的通项公式；
\((2)\)记\(T _{n} =a _{n} b _{1} +a _{n-1} b _{2} +…+a _{1} b _{n}\)，\(n∈N ^{*}\)，求\(T _{n}\)．