已知等差数列\(\{a_{n}\}\)的前\(n\)项和味\(S_{n}\)，\(a_{1} > 0\)，\(a_{1}⋅a_{2}= \dfrac {3}{2}\)，\(S_{5}=10\)．
\((1)\)求数列\(\{a_{n}\}\)的通项公式；
\((2)\)记数列\(b_{n}= \begin{cases} \overset{2^{a_{n}},n{为奇数}}{a_{n},n{为偶数}}\end{cases}\)，求数\(\{b_{n}\}\)的前\(2n+1\)项和\(T_{2n+1}\)．