已知正项数列\(\{a _{n} \}\)的前\(n\)项和为\(S _{n}\)，且满足\(8S _{n} =16a _{n} ^{2} +n-1\)，数列\(\{b _{n} \}\)满足\(b _{n} = \sqrt {2}b_{n-1} (n\geqslant 2)\)，\(b _{1} = \dfrac { \sqrt {2}}{2}\)．
\((\)Ⅰ\()\)求数列\(\{a _{n} \}\)、\(\{b _{n} \}\)的通项公式；
\((\)Ⅱ\()\)记数列\(\{c _{n} \}\)满足\(c _{n} =[(-1) ^{n-1} +1]a _{n} +[(-1) ^{n} +1]b _{n}\)，设数列\(\{ \dfrac {c_{2n-1}}{c_{2n}}\}\)的前\(n\)项和为\(A _{n}\)，数列\(\{ \dfrac {2}{c_{2n-1}C_{2n+1}}\}\)的前\(n\)项和为\(B _{n}\)，试比较\(A _{n}\)与\(B _{n}\)的大小．