已知抛物线\(C:{{y}^{2}}=2px(p > 0)\)的焦点为\(F\)，点\(M\left( {{x}_{0}},2\sqrt{2} \right)({{x}_{0}} > \dfrac{p}{2})\)是抛物线\(C\)上一点，圆\(M\)与线段\(MF\)相交于点\(A\)，且被直线\(x=\dfrac{p}{2}\)截得的弦长为\(\sqrt{3}\left| MA \right|.\)若\(\dfrac{\left| MA \right|}{\left| AF \right|}=2\)，则\(\left| AF \right|\)等于(    )