已知\(\{a _{n} \}\)为等差数列，\(\{b _{n} \}\)为等比数列且公比大于\(0\)，\(a _{1} =1\)，\(b _{1} =2\)，\(2a _{3} =5(a _{5} -a _{4} )\)，\(2b _{3} =b _{5} -b _{4}\)．
\((\)Ⅰ\()\)求\(\{a _{n} \}\)和\(\{b _{n} \}\)的通项公式；
\((\)Ⅱ\()\)设\(c_{n}=(-1)^{n+1}( \dfrac {4n}{a_{n}\cdot a_{n+1}}- \dfrac {1}{b_{n}})(n∈N^{*})\)，记数列\(\{c _{n} \}\)的前\(n\)项和为\(S _{n}\)，求\(S _{n}\)．