已知\(f(x)\)为定义在实数集\(R\)上的奇函数，且在\((0,+\infty)\)内是增函数，又\(f\left(2\right)=0\)，则不等式\(x\cdot f\left(1-x\right)< 0\)的解集是\((\quad)\)
A. \(\left(-\infty,-2\right)\bigcup\left(-1,0\right)\bigcup\left(2,+\infty\right)\)
B. \(\left(-\infty,-2\right)\bigcup\left(2,+\infty\right)\) C. \(\left(-1,0\right)\bigcup\left(1,3\right)\) D. \(\left(-\infty,-1\right)\bigcup\left(0,1\right)\bigcup\left(3,+\infty\right)\)
