已知等比数列\(\{a_{n}\}\)的公比为\(q(q≠1)\)，前\(n\)项和为\(S_{n}\)，\(S_{3}=14\)，且\(3a_{2}\)是\(2a_{3}\)与\(4a_{1}\)的等差中项．
\((1)\)求\(\{a_{n}\}\)的通项公式；
\((2)\)设\(b_{n}=\dfrac{1}{(\log_{2}a_{n+1})(\log_{2}a_{n+2})}\)，\(\{b_{n}\}\)的前\(n\)项和为\(T_{n}\)，证明：\(T_{n}< \dfrac {1}{2}.\)