已知数列\(\{a_{n}\}\)是等差数列，其前\(n\)项和为\(S_{n}\)，数列\(\left\{ \left. b_{n} \right. \right\}\)是公比大于\(0\)的等比数列，且\(b_{1}=-2a_{1}=2\)， \(a_{3}+b_{2}=-1\)， \(S_{3}+2b_{3}=7\)．

\((1)\)求数列\(\{a_{n}\}\)和\(\left\{ \left. b_{n} \right. \right\}\)的通项公式；

\((2)\)令\(c_{n}=\begin{cases} 2,n为奇数 \\ \dfrac{-2a_{n}}{b_{n}},n为偶数 \end{cases}\)，求数列\(\left\{ \left. c_{n} \right. \right\}\)的前\(n\)项和\(T_{n}\)．